Accepted solution

URI 1178 Solution

Open original problem
Source code

#include <iostream>

#include<iomanip>

#include<stdio.h>

using namespace std;

int main()

{

      double N[100];

      double X;

    cin>>X;

    for(int i=0;i<100;i++)

    {

        N[i]=X;

        X=X/2.0000;

        printf("N[%d] = %.4lf
",i,N[i]);

    }

    return 0;

}
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