URI 1037 solution

#include <stdio.h>

int main() {

      double n;

    scanf("%lf",&n);

    if(n>=0 && n<=25)

    {

        printf("Intervalo [0,25]
");

    }

    else if(n>25 && n<=50)

    {

        printf("Intervalo (25,50]
");

    }

    else if(n>50 && n<=75)

    {

         printf("Intervalo (50,75]
");

    }

    else if(n>75 && n<=100)

    {

         printf("Intervalo (75,100]
");

    }

    else printf("Fora de intervalo
");

    return 0;

}