Accepted solution

Divisible Sum Pairs(Hacker Rank)

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Source code

int divisibleSumPairs(int n, int k, vector<int> ar)

 {

     int count=0;

    for(int i=0;i<ar.size();i++)

    {

        for(int j=i+1;j<ar.size();j++)

        {

            if((ar[i]+ar[j])%k==0)

            {

                count++;

            }

        }

    }

    return count;

}
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