Accepted solution

950A - Left-handers Right-handers and Ambidexters

Open original problem
Source code

#include <iostream>

#include<vector>

#include<string>

#include<math.h>

#include<set>

#include<map>

#include<list>

#include<stack>

#include<queue>

#include <fstream>

#include<iterator>

#include<algorithm>

#include <iomanip>      // std::setprecision

/* ==================================================

  |                                                  |

  |    Author: *** S. M. Sabiul Hajjaj Sabit ***     |

  |       Last Edit:  May,14,2019                    |

   ================================================== */

///***global declaration***///

#define all(arr) arr.begin(),arr.end()

#define pb push_back

#define lb lower_bound

#define up upper_bound

#define sz(x) x.size()

#define min3(a,b,c)  min(min(a,b),c)

#define max3(a,b,c)  max(max(a,b),c)

#define lli long long int

#define prnt(x) cout<<x<<endl

using namespace std;

int j,n,m,sum=0,ans=0;

template <typename T>long long int power(T a, T b)

{

    long long int pow=1;

    for(int i=0; i<b; i++)

        pow *= a;

    return pow;

}

/**** ascending sort vector of pair basis fd 2nd element******/

//sort(arr.begin(), arr.end(),sortbysec);

bool sortbysec(const pair<int,int> &a,const pair<int,int> &b)

{

    return (a.second < b.second);

}

/////*********Write Code From Here*********///

int main()

{

    int l,r,a;

    cin>>l>>r>>a;

    if(l==r)

    {

        prnt(l+r+(a-a%2));

    }

    else if(l<r)

    {

        int t = r-l;

        if(t<=a)

        {

            l+=t;

            a-=t;

        }

        else

        {

            l+=a;

            a=0;

        }

        prnt((min(l,r)*2)+(a-a%2));

    }

    else

    {

        int t = l-r;

        if(t<=a)

        {

            r+=t;

            a-=t;

        }

        else

        {

            r+=a;

            a=0;

        }

        prnt((min(l,r)*2)+(a-a%2));

    }

}
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