Find those Person Whose Age Will be at Last 18 with Lined List in C++ .

#include <iostream>

using namespace std;

struct list

{

    char name[100];

    int year;

    struct list *next;

};

typedef struct list node;

node *start=NULL;

void insert_node()

{

    node *last;

    if(start==NULL)

    {

        start = new node();

        cout<<"Name: ";

        cin>>start->name;

        cout<<"Birth Year: ";

        cin>>start->year;

    }

    else

    {   node * temp = new node();

        cout<<"Name: ";

        cin>>temp->name;

        cout<<"Birth Year: ";

        cin>>temp->year;

        temp->next= NULL;

        last = start;

        while(last->next!=NULL)

        {

            last = last->next;

        }

        last->next= temp;

    }

}

void show()

{

    node *temp=start;

    cout<<"
 People Over 18 years: "<<endl;

    while(temp!=NULL)

    {

        if((2018-temp->year)>=18) ///find the age who is more then 18

        {

            cout<<temp->name<<endl;

        }

        temp = temp->next;

    }

}

int main()

{

    int flag=1;

    while(flag==1)

    {

        cout<<"Press 1 to Enter New Node: ";

        cin>>flag;

        if(flag!=1)break;

        insert_node(); ///call this function to insert new node

    }

    show(); ///print function

    return 0;

}