Solve Math Equation using operators in C

Equation:  X =  (3.31 * n2 + 2.01 * m3) / (7.16 * m2 + 2.01 * n3)

Code:

#include <stdio.h>

int main()

{

    double n,m;

    double ans;

 

    printf("Please Enter Two Value: ");

    scanf("%lf %lf",&n,&m);

    ans =  (3.31 * (n*n) + 2.01 * (m*m*m)) / (7.16 * (m*m) + 2.01 * (n*n*n));

    printf("Answer is: %.4lf
",ans);

   return 0;

}